b: \(=72\cdot4-3=288-3=285\)

a) `27 .75 + 25.27 -150`

`=27 xx (75 + 25)-150`

`=27 xx 100-150`

`=2700-150`

`=2550`

b) `142-[50-(2^3 .10-2^3 .5)]`

`=142-[50-2^3 .(10-5)]`

`=142-(50-8 .5)`

`=142-(50-40)`

`=142-10`

`=132`

c) `375:{32-[4+(5.3^2-42)]}-14`

`=375:{32-[4+(45-42)]}-14`

`=375:[32-(4+3)]-14`

`=375: 25 -14`

`=15-14`

`=1`

a. 27 . 75 + 25 . 27 - 150

= 27. (75 + 25) - 150

= 27 . 100 - 150

= 2700 - 150

= 2550

b. 142 - [50 - (2³.10 - 2³.5)]

= 142 - [50 - (8 . 10 - 8 . 5)]

= 142 - {50 - [8 . (10 - 5)]} 

= 142 - (50 - 40)

= 142 - 10

= 132

c. 375 : {32 – [ 4 + (5. 3² – 42)]} – 14

= 375 : {32 – [ 4 + (5. 9 – 42)]} – 14

= 375 : {32 – [ 4 + (45 – 42)]} – 14

= 375 : {32 – [ 4 + 3]} – 14

= 375 : {32 –7} – 14

= 375 : 25 - 14

= 15 - 14

= 1

các bạn ơi xin các bạn tội ngiệp cho tôi vài lik eSky Nguyễn

a).

= 27. (75+25)- 150

= 27. 100 -150

= 2700    - 150

= 2550

a) 12 : { 400 : [ 500 - ( 125 + 25 . 7 )]}

= 12 : { 400 : [ 500 - ( 125 + 175 )]}

= 12 : { 400 : [ 500 - 300 ]}

= 12 : { 400 : 200 }

= 12 : 2 

= 6

b) 5 . 22 - 18 : 3

= 110 - 6

= 104

c) 18 : 3 + 182 + 3 . ( 51 : 17 )

= 6 + 182 + 3.3

= 6 + 182 + 9

= 197

d) 25.8 - 12.5 + 170 : 17 - 8

= 1000 - 60 + 10 - 8

= 940 + 10 - 8

= 940 + 2

= 942

\(a,\dfrac{5^{16}\cdot27^7}{125^5\cdot9^{11}}=\dfrac{5^{16}\cdot\left(3^3\right)^7}{\left(5^3\right)^5\cdot\left(3^2\right)^{11}}\)

\(=\dfrac{5^{16}\cdot3^{21}}{5^{15}\cdot3^{22}}=\dfrac{5}{3}\)

\(b,\left(-0,2\right)^2\cdot5-\dfrac{2^{13}\cdot27^3}{4^6\cdot9^5}\)

\(=0,04\cdot5-\dfrac{2^{13}\cdot\left(3^3\right)^3}{\left(2^2\right)^6\cdot\left(3^2\right)^5}\)

\(=0,2-\dfrac{2^{13}\cdot3^9}{2^{12}\cdot3^{10}}\)

\(=0,2-\dfrac{2}{3}\)

\(=-\dfrac{7}{15}\)

\(c,\dfrac{5^6+2^2\cdot25^3+2^3\cdot125^2}{26\cdot5^6}\)

\(=\dfrac{5^6+2^2\cdot\left(5^2\right)^3+2^3\cdot\left(5^3\right)^2}{5^6\cdot26}\)

\(=\dfrac{5^6+4\cdot5^6+8\cdot5^6}{5^6\cdot26}\)

\(=\dfrac{5^6\left(1+4+8\right)}{5^6\cdot26}\)

\(=\dfrac{13}{26}\)

\(=\dfrac{1}{2}\)

#\(Toru\)

\(a,\dfrac{5^{16}.27^7}{125^5.9^{11}}=\dfrac{\left(5^2\right)^8.9^7.3^7}{25^5.5^5.9^{11}}\\ =\dfrac{25^8.9^7.\left(3^2\right)^3.3}{25^5.\left(5^2\right)^2.5.9^{11}}=\dfrac{25^8.9^7.9^3.3}{25^5.25^2.5.9^{11}}\\ =\dfrac{25^8.9^{10}.3}{25^7.5.9^{11}}=\dfrac{25^7.9^{10}.25.3}{25^7.9^{10}.5.9}\\ =\dfrac{25.3}{5.9}=\dfrac{5.5.3}{5.3.3}=\dfrac{5}{3}\)

a) 27 . 75 + 25 . 27 - 150 = 2025 + 675 - 150 = 2700 - 150 = 2550.

Lưu ý. Có thể dùng tính chất phân phối của phép nhân đối với phép cộng để nhẩm:

27 . 75 + 25 . 27 - 150 = 27 . (75 + 25) - 150 = 27 . 100 - 150 = 2700 - 150 = 2550.

b) 12 : {390 : [500 - (125 + 35 . 7)]} = 12 : {390 : [500 - (125 + 245)]}

= 12 : [390 : (500 - 370)] = 12 : (390 : 130) = 12 : 3 = 4.

a,27+75.25+27-150

= 27.(75+25)-150

=27.100-150

=2700-150

=2550

b,12:{390:[500-(125+35.7)]}

=12:{390:[500-(125+245)]}

=12:{390:[500-370]}

=12:{390:130}

=12:3

=4

Thank you very much

a)\(27.75+25.27-150=27\left(75+25\right)-150\)

\(=27.100-150\)

\(=2700-150\)

\(=2550\)

b)\(12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}=12:\left\{390:\left[500-\left(125+245\right)\right]\right\}\)

\(=12:\left[390:\left(500-370\right)\right]\)

\(=12:\left(390:130\right)\)

\(=12:3\)

=4

a, 25.(75 + 27 - 150 )

= 25 . (-48)

= - 1200

b, 12 : { 390 : [500 - 370 ]

= 12 : { 390 : 130 }

= 12 : 3

= 4

a) \(27.75+25.27-150\)

\(=27.\left(75+25\right)-150\)

\(=27.100-150\)

\(=2700-150\)

\(=2550\)

b) \(12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\)

\(=12:\left\{390:\left[500-370\right]\right\}\)

\(=12:\left\{390:130\right\}\)

\(=12:3\)

\(=4\)

a, 27.75+25.27-150=27.(75+25)-150

                               =27.100-150

                              =2700-150

                              =2550

b,12:{390:[500-(125+35.7)]}

=12:{390:[500-(125+245)]}

=12:{390:[500-370]}

=12:{390:130}

=12:3

=4.